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Must Read:- All Jamb 2017 Candidate Enter Here And Drop Your Nums

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We are creating this form to know those that will need help concerning jamb 2017 updates as the sales of jamb 2017 form kicksoff…. So we at Bamsforum are eager ready to render help by providing means of you to secure 200-250 since you know the new jamb policy on admission centers on you aiming high in your jamb score…

So start commenting below and get prepared for us

About Nb Admin!

270 comments

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  175. (3a)

    E.M.F (E) = 3.00v , Io = 0.62A

    S/N | PJ=L(cm) | I(A) | y=E/A(v/A) |
    1. | 20.00 | 0.58 | 5.172 |
    2. | 30.00 | 0.50 | 6.000 |
    3. | 40.00 | 0.45 | 6.667 |
    4. | 50.00 | 0.40 | 7.500 |
    5. | 60.00 | 0.35 | 8.571 |
    6. | 70.00 | 0.32 | 9.375 |

    (Vii)
    Slope(s)= Y2 – Y1 / L2 – L1
    S = 10.20 – 4.00/ 80 – 7
    S = 6.20/73
    S= 0.0849v/A
    The intercept C on the vertical axis = 2.70v/A

    (Viii)
    K = Io C
    K = 0.62 x 2.70
    K = 1.674 to get d rest and for all subject whatsapp or cal 07063716823

  176. (1a)
    PLS DRAW A TABLE:

    i|Mi(cm)|Mi(g)|Li(cm)(Raw)|Li(cm)(Real)|e=li-lo:
    1|4.75 |47.50 |2.60|5.20 |1.40|
    2|6.13 |61.30 |3.15|6.30 |2.50|
    3|8.53 |85.80 |3.72|7.40 |3.60|
    4|10.43|104.30|4.30|8.60 |4.80|
    5|12.28|122.80|4.85|9.70 |5.90|
    6|14.20|142.00|5.40|10.80|7.00|

    Slope= De(cm)/DM(g) = e2-e1/M2-M1

    (1aviii)
    -I avoided parallex error when taking the reading
    -I would ensure that the masses do not touch the ground.
    -I would ensure that the support is rigid

    (1bi) This means that the ratio of force to extension is 10Nm-1

    (1bii) E = 1/2Ke^2
    but F=ke
    .:. E = F/k
    E= 1/2k(F/K)^2
    E=F^2/2k
    ============

    (3ai)
    TABULATE
    i|X(n)|Y(n)|V(v)|Z=V^-1|R(n)
    1|2|2|1.50|0.67|1.00
    2|6|3|1.30|0.77|2.00
    3|12|4|1.14|0.88|3.00
    4|20|5|1.00|1.00|4.00
    5|30|6|0.91|1.10|5.00

    Precaution:
    -I will ensure tight connections of all wires
    -i would ensure that the key is opened during each reading

    (3bi)
    R=(2*3)/(2+3)+0.8
    R=1.20+0.8
    R=2.0ohms
    But I=E.M.F/R+r
    I=E/2+r
    2I+Ir=E
    Ir=E-2I
    r=(E-2I)/I

    (3bii)
    V=IR
    =2.6*4
    V=10.40volts
    ==============to get d rest abswer ib alk subject
    whatsapp us cal 07063716823

  177. (1a)
    PLS DRAW A TABLE:

    i|Mi(cm)|Mi(g)|Li(cm)(Raw)|Li(cm)(Real)|e=li-lo:
    1|4.75 |47.50 |2.60|5.20 |1.40|
    2|6.13 |61.30 |3.15|6.30 |2.50|
    3|8.53 |85.80 |3.72|7.40 |3.60|
    4|10.43|104.30|4.30|8.60 |4.80|
    5|12.28|122.80|4.85|9.70 |5.90|
    6|14.20|142.00|5.40|10.80|7.00|

    Slope= De(cm)/DM(g) = e2-e1/M2-M1

    (1aviii)
    -I avoided parallex error when taking the reading
    -I would ensure that the masses do not touch the ground.
    -I would ensure that the support is rigid

    (1bi) This means that the ratio of force to extension is 10Nm-1

    (1bii) E = 1/2Ke^2
    but F=ke
    .:. E = F/k
    E= 1/2k(F/K)^2
    E=F^2/2k
    ============

    (3ai)
    TABULATE
    i|X(n)|Y(n)|V(v)|Z=V^-1|R(n)
    1|2|2|1.50|0.67|1.00
    2|6|3|1.30|0.77|2.00
    3|12|4|1.14|0.88|3.00
    4|20|5|1.00|1.00|4.00
    5|30|6|0.91|1.10|5.00

    Precaution:
    -I will ensure tight connections of all wires
    -i would ensure that the key is opened during each reading

    (3bi)
    R=(2*3)/(2+3)+0.8
    R=1.20+0.8
    R=2.0ohms
    But I=E.M.F/R+r
    I=E/2+r
    2I+Ir=E
    Ir=E-2I
    r=(E-2I)/I

    (3bii)
    V=IR
    =2.6*4
    V=10.40volts
    ==============to get d rest answer in all subject
    whatsapp us cal 07063716823

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